a^2=226

Solution for a^2=226 equation:

a^2=226

We move all terms to the left:

a^2-(226)=0

a = 1; b = 0; c = -226;
Δ = b2-4ac
Δ = 02-4·1·(-226)
Δ = 904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{904}=\sqrt{4*226}=\sqrt{4}*\sqrt{226}=2\sqrt{226}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{226}}{2*1}=\frac{0-2\sqrt{226}}{2}
=-\frac{2\sqrt{226}}{2}
=-\sqrt{226}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{226}}{2*1}=\frac{0+2\sqrt{226}}{2}
=\frac{2\sqrt{226}}{2}
=\sqrt{226}
$